20x^2-13x-35=0

Solution for 20x^2-13x-35=0 equation:

20x^2-13x-35=0

a = 20; b = -13; c = -35;
Δ = b2-4ac
Δ = -132-4·20·(-35)
Δ = 2969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{2969}}{2*20}=\frac{13-\sqrt{2969}}{40}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{2969}}{2*20}=\frac{13+\sqrt{2969}}{40}
$